Johannesburg. So far, Shardul Tagore has performed well in the second Test. In the first innings (India vs South Africa) he sent six South African batsmen to the pavilion. This is the best performance of an Indian bowler on the field. Due to which Team India managed to prevent South Africa from taking a big lead in the first innings. He made a significant contribution by playing a good innings with the bat in the second innings on Wednesday. Team India’s lead is over 200 runs.
Shardul Tagore was dismissed for 28 off 24 balls in the second innings. He hit 5 fours and a six. In other words, he scored 26 runs from the boundary. He hit two fours in one over off fast bowler Marco Jensen. Virat Kohli, Mayank Agarwal and batting coach Vikram Rathore could not stop laughing when they saw his four. Coach Rahul Dravid Also gave applause. Before this match, Shardul has played more than 50 runs in 6 innings of 3 Tests. Maximum 6 run innings.
The average is also good in the first class
Shardul Tagore has also done well in first-class cricket with both bat and ball. He has scored 1458 runs at an average of 17 in 92 innings of 67 matches before this match. Has made 9 half centuries. Played a big innings of 7 runs. He also took 223 wickets at an average of 26. He has taken 5 wickets 12 times. His best performance was 7 for 31.
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As of this writing, Team India has scored 245 runs for the loss of 9 wickets in the second innings. His total lead has been 218 runs. Hanuma Bihari is playing for 20 runs. India scored 202 and South Africa 229 in the first innings.
Tags: Cricket News, India vs. SA, India vs South Africa, Rahul Dravid, Shardul Tagore, Team India, Virat Kohli